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Bulk updating multiple columns in oracle

Then you can give the following insert statement Insert into emp (empno, ename, sal) select empno, ename, sal from old_emp; Suppose we have sales table with the following structure.

Sales Now we want to add the rows from SALES table Weekly_Sales Table in the following Structure.

When I try to update only the missing data the non-matched data is also updated but to NULL. The reason some of your rows are getting NULLs updated is due to the subquery.

When the subquery fails to find a matching row in tbl B, the subquery returns NULL.

If you want to review the complete syntax of the UPDATE statement then please refer to Books Online.

To properly show you how to use the UPDATE statement I will need to create a few tables to hold some sample data. Below is the code to create my Toy table: In order to show you how to UPDATE a table from data in another table I need to build a second sample data table that I will call New Toy Price.

SQL In the MERGE statement above, Jack, Caledon and Fabrizio’s records were not deleted from the table STUDENTS though their scores are below 640, since the delete condition works on the source, not the target. Interestingly, I have found it hard to get managers to agree to using it – they don’t like the sequence gaps and the fact that inserts and update counts aren’t reported individually. Hi, How do you know to know the id of the row that has been inserted OR updated? A workaround is to add a couple of tracking columns to the target table: transaction_type, transaction_date.Let’s say this is how STUDENT_N looks before it is merged with STUDENT: merge into student a 2 using 3 (select id, name, score 4 from student_n) b 5 on (= b.id) 6 when matched then 7 update set = 8 , a.score = b.score 9 when not matched then 10 insert (a.id, a.name, a.score) 11 values (b.id, b.name, b.score); 5 rows merged.select * from student; ID NAME SCORE ---------- --------------- ---------- 1 Jack 540 2 Rose 3 William 650 4 Caledon 620 5 Fabrizio 600 6 Thomas 7 Ruth 690 11 Brock 705 10 Lizzy 9 Wallace 600 8 Spicer 620 11 rows selected. But it does not work with a merge query (probably because of the update part): “Missing IN or OUT parameter at index:: 1” Would would you advise to retrieve the value of a field (typically an id) of the row that has been inserted or updated?If this happens, the UPDATE will terminate with an error ("subquery may return only one row"). It used to be that you could not BULK COLLECT into an ARRAY OF RECORDS but that you could into a RECORD OF ARRAYS, as above. = 'Rectifier' THEN v_part.delete(rec); END IF; END LOOP; FORALL idx CREATE TABLE valid_orders ( cust_name VARCHAR2(32), amount NUMBER(10,2)); CREATE TABLE big_orders AS SELECT * FROM valid_orders WHERE 1 = 0; CREATE TABLE rejected_orders AS SELECT * FROM valid_orders WHERE 1 = 0; DECLARE SUBTYPE cust_name IS valid_orders.cust_name%TYPE; TYPE cust_typ IS TABLe OF cust_name; cust_tab cust_typ; SUBTYPE order_amount IS valid_orders.amount%TYPE; TYPE amount_typ IS TABLE OF NUMBER; amount_tab amount_typ; cust_tab := cust_typ('Company1', 'Company2', 'Company3', 'Company4', 'Company5'); amount_tab := amount_typ(5000.01, 0, 150.25, 4000.00, NULL); END setup_data; BEGIN setup_data; dbms_output.put_line('--- Original order data ---'); FOR i IN 1..cust_tab.If you are an application programmer then you will more than likely need to write TSQL code to update your SQL Server database tables.In order to update a row in a SQL Server table you will use the UDPATE statement.Consider another table STUDENT_N, which holds updates for the target table STUDENT.Every week, table STUDENT needs to be synchronized with the data in STUDENT_N – any new entries for students who attempted the GMAT to be inserted, plus corrections if any made to the existing details.For example We want to change the name of employee no 102 from ‘Sami’ to ‘Mohd Sami’ and to raise the salary by 10%. update emp set name=’Mohd Sami’, sal=sal (sal*10/100) where empno=102; Now we want to raise the salary of all employees by 5%.update emp set sal=sal (sal*5/100); Now to change the names of all employees to uppercase.


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